ln((2/3)e^-6x)=1

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Solution for ln((2/3)e^-6x)=1 equation: 


D( x )

(2/3)*e^-6*x <= 0

(2/3)*e^-6*x <= 0

(2/3)*e^-6*x <= 0

2/3*e^-6*x+0 <= 0 // - 0

2/3*e^-6*x <= 0 // : 2/3*e^-6

x <= 0/(2/3*e^-6)

x <= 0

x in (0:+oo)

ln((2/3)*e^-6*x) = 1 // - 1

ln((2/3)*e^-6*x)-1 = 0

ln((2/3)*e^-6*x)-1 = 0 // + 1

ln((2/3)*e^-6*x) = 1

ln((2/3)*e^-6*x) = ln(e^1)

(2/3)*e^-6*x = e^1

(2/3)*e^-6*x-e^1 = 0

2/3*e^-6*x-e = 0 // + e

2/3*e^-6*x = e // : 2/3*e^-6

x = e/(2/3*e^-6)

x = 3/2*e^7

x = 3/2*e^7

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